# In equilateral triangle ABC, point O is the intersection of the heights drawn from

August 29, 2021 | education

| **In equilateral triangle ABC, point O is the intersection of the heights drawn from the vertices to the bases. Determine the angle between the heights of the triangle.**

Since ABC is an equilateral triangle, its angles are 60˚. The heights drawn from the vertices are also bisectors that divide the angle in half: 60˚ / 2 = 30˚.

This means: angle BAO = angle ABO = 30˚.

Find the angle AOB.

Angle AOB = 180˚ – 30˚ – 30˚ = 120˚.

Answer: the angle between the heights of the triangle is 120˚.

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